Key claim

The comfortable belief under pressure: a broadened peak in a spectral function is simply a delta-function energy level with a finite lifetime attached to it.

Theme

From real-axis poles to resonances and branch cuts: when spectral broadening is physical—and when it is only a regulator.

Guiding question

The same Lorentzian appears in operator spectral theory, many-body Green functions, and classical damped response.

Does it represent the same physical object in all three cases, or are we confusing a mathematical boundary value, an effective decay law, and genuine dissipation?

Setup

Take a discrete state |d⟩ coupled to many environmental states |k⟩:

H=ϵd|d⟩⟨d|+∑kϵk|k⟩⟨k|+∑k(Vk|d⟩⟨k|+h.c.).

For a finite system, the projected retarded resolvent has the exact representation

GdR(z)=⟨d|(z−H)−1|d⟩=∑nZnz−En,

and

Ad(ω)=−1πImGdR(ω+i0+)=∑nZnδ(ω−En),

where

Zn=|⟨d|n⟩|2.

Eliminating the k-states gives

GdR(z)=1z−ϵd−Σ(z),Σ(z)=∑k|Vk|2z−ϵk.

After a continuum limit,

ΣR(ω)=Δ(ω)−iκ(ω),

so that

Ad(ω)=1πκ(ω)[ω−ϵd−Δ(ω)]2+κ(ω)2.

This is the smallest model in which exact poles, a continuum self-energy, and an apparently decaying quasiparticle can all be separated cleanly.

Analysis

Derivation — the resolvent is a spectral measure

For every finite-dimensional closed system with self-adjoint H, the spectrum is real and Ad is a sum of delta functions.

The i0+ does not shift the eigenvalues or give them lifetimes. It selects a boundary value of an analytic function:

1x+i0+=PV1x−iπδ(x).

The imaginary part appears because the real axis contains spectral support, not because an infinitesimal physical damping has been added.

More abstractly, Ad(ω)dω is the spectral measure of H associated with |d⟩. It answers:

How is the vector |d⟩ distributed over the exact energy decomposition of the Hamiltonian?

At this stage, it is not a statement about particles, decay, or experimental resolution.

Scope and assumptions — irreversibility requires a singular limit

At finite N,

⟨d|e−iHt|d⟩=∑nZne−iEnt

is quasiperiodic. Probability leaves |d⟩, but recurrences remain possible. There is no exact irreversible exponential decay for arbitrarily late times.

A smooth linewidth appears only after replacing the discrete bath by a continuum or introducing finite experimental resolution. The dangerous order of operations is

N⟶∞before probing sufficiently long times.

As the bath level spacing tends to zero, recurrence times diverge and phase information disperses into increasingly many modes. A resonance pole

z⋆≃E⋆−iκ⋆

can then govern an intermediate-time regime.

Even that pole usually does not determine all times:

  • Very short times are generically quadratic rather than exponential.
  • Band edges and thresholds generate nonexponential late-time tails.
  • Bound-state poles outside the continuum can leave a nondecaying component.

A “lifetime” is therefore normally an intermediate-scale statement.

Physical interpretation — classical damping matches only one layer

A damped classical mode has susceptibility

χR(ω)∼1ω−ω0+iκ,

and its causal time response contains

θ(t)e−iω0t−κt.

The correspondence must be graded carefully.

Mathematical identity: Fourier transforming a simple lower-half-plane pole gives a causal exponential term.

Controlled physical approximation: if ΣR(ω) varies slowly across a narrow resonance, it may be replaced locally by Δ⋆−iκ⋆.

Suggestive analogy: the quantum resonance may then be discussed as though it were a classically damped oscillator.

The dictionary eventually breaks. A closed quantum system need not possess microscopic friction; its apparent damping can be dephasing into unresolved degrees of freedom.

In this model, Ad is a projected spectral measure. In a general many-body problem, a spectral function records addition and removal transition weights.

Classical dissipated power is instead tied to ImχR. Relating response to fluctuations requires extra information, such as a state and the fluctuation–dissipation theorem.

False claim to diagnose

A Lorentzian spectral peak proves that the underlying Hermitian Hamiltonian has a complex eigenvalue E−iκ.

Why is this tempting? The Lorentzian is generated by 1/(ω−E+iκ), whose pole is complex.

The failure is that a self-adjoint Hamiltonian has real spectrum. The complex pole belongs to an analytically continued Green function—often on a second Riemann sheet—or to an effective projected non-Hermitian description.

It is not an ordinary normalizable eigenstate of the full closed Hamiltonian.

What survives is narrower:

An isolated second-sheet pole can accurately govern a resonance’s intermediate-time amplitude and line shape when background and threshold contributions vary slowly nearby.

What follows — and what does not

The disagreement is primarily an order-of-limits problem, sharpened by a choice of observables.

The exact finite-system spectral measure resolves every eigenstate. The effective Green function observes only the d-sector after the bath has been eliminated.

Taking a continuum limit and discarding bath-resolved phase information can convert reversible dephasing into effective decay.

A finite −ImΣR is therefore physical when it represents continuum decay channels. But “physical” does not mean “a complex energy eigenvalue of the full Hamiltonian.”

The key distinction is:

  • i0+ selects the causal boundary value.
  • A finite −ImΣR encodes available decay channels after the relevant continuum or resolution limit.

Exercise

Consider a flat continuum with density ρ, coupling V, and energies ϵ∈[−D,D]:

ΣR(ω)=ρ|V|2∫−DDdϵω−ϵ+i0+.
  1. Derive its real and imaginary parts.
  2. Take the wide-band regime |ω|≪D and obtain the Lorentzian spectral function.
  3. Explain why the exact finite-band dynamics cannot be purely exponential for all t>0.
Hint 1

Use

1x+i0+=PV1x−iπδ(x).
Hint 2

Inspect the nonanalytic points at ω=±D. Long-time Fourier behavior is controlled by singularities and endpoints, not only by the resonance pole.

Oral check 1. What conceptual error is made by replacing i0+ with a finite constant iη and immediately calling 1/η a lifetime?

Oral check 2. Why can exponential decay be extremely accurate experimentally even though it is not exact at arbitrarily short or long times?

Solution

The distribution identity gives

ΣR(ω)=ρ|V|2[ln⁡|ω+Dω−D|−iπΘ(D−|ω|)].

Thus, inside the band,

Δ(ω)=ρ|V|2ln⁡|ω+Dω−D|,κ=πρ|V|2.

For |ω|≪D,

ln⁡|ω+Dω−D|=2ωD+O(ω3D3),

so the real part varies slowly and can be absorbed locally into an energy shift and residue renormalization. Then

GdR(ω)≃1ω−ϵdren+iκ,

which gives

Ad(ω)≃1πκ(ω−ϵdren)2+κ2.

The pole contribution to the causal time response is proportional to e−κt for t>0.

The exact self-energy has logarithmic branch points at ω=±D. A contour deformation therefore receives both resonance-pole and branch-cut contributions.

The branch cut produces nonexponential late-time behavior. Depending on the parameters and band structure, poles outside the continuum can also leave residual nondecaying weight.

Check your understanding

In the present model, is a quasiparticle best defined as an approximate eigenstate, a pole of an analytically continued correlator, or a concentration of spectral weight?

Which definition do you regard as most fundamental? Reply with your derivation, or simply say “deeper,” “too easy,” or “too hard.”

Connections and next step

  • New pressure point: causal regulators versus physical linewidths.
  • Main domains: spectral theory, many-body response, and classical damping.
  • Toy model: a Fano–Anderson discrete level coupled to a flat finite band.
  • Unresolved: the physical status of second-sheet poles.
  • Revisit: boundary conditions and effective descriptions in three to four runs.